Question

A car traveling at a speed of 54km/h is brought to rest in 90 seconds. find the retardation and distance travelled by the car before coming to rest?

Answer 1

v=u+at
u=54kmph=54*(5/18)
=15 m/s
v=0
0=15+a(90)
a=-1/6 m/s^2
v^2-u^2=2as
0-225=-2(1/6)s
s=675 m