A car traveling at a speed of 90 km ( 25 m/s) per hour steps after 3 s when the brake is applied. If the mass of the car including passengers is 1200 kg, what is the force applied when the brake is operated?
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we have initial velocity 90 km/h = 25 m/s
time = 3 second
and mass of car including passenger = 1200 kg
final velocity of a car = 0 m/s we have to find the force
as we know f = mxa
here mass is given but acceleration is not given so we have to find acceleration.
so we have u,v and t
now we have
V = u+at
0 = 25+ax3
0= 25+3a
a = 28 m/s
so acceleration = 28m/s
now we have f= mxa
f = 1200x28=33600 N
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