Question

A car traveling at constant velocity, passes a
stationary motorcycle at a traffic light. As the car
overtakes the motorcycle, the motorcycle accelerates
uniformly from rest for 10 s. The following positiontime
graph represents the motions of both vehicles
from the traffic light onwards.
a. Use the graph to find the constant velocity of the
car.
b. Use the information from the graph to find the
magnitude of the acceleration of the motorcycle.
c. Calculate how long (in seconds) it will take the
motorcycle to catch up with the car (point X).
d. How far behind the motorcycle will the car be after 15 seconds?

Answer 1

here!

1) magnitude of velocity of car

v = slope of stright x,-t graph

= ∆x/∆t

=

 

 

= (100-0)/(10-0)

 

= 100/10

 

= 10 m/s

 

2) Time taken by motorbike to catch car :

 

t = time where both curves meet

 

= 15 s

 

 

3) distance between car and motorcycle :

 

The S = distance covered by car - Dist covered by

motorcycle in 10 s

= 100 - 75

 

 

= 25 m

After 10 s motor cycle is 25m behind the car