A car traveling at rate of 40 km/ h left bokaro a second car left bokaro one hour later at what speed must the second car travelle to catch up the first car in 4 hours
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Answer:
Speed of second car =53.33km/hr
Explanation:
Speed of first car =40km/h
Time taken by first car =4hrs
Distance covered by first car =Speed× Time
=40km×4hr
=160km
Distance covered by first car =Distance covered by second car
Time taken by second car =4hrs-hrs
=3hrs
Speed of second car =Distance ÷Time
=160km÷3hrs
=53.33km/hr
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