Physics, asked by prithamreddy2004, 8 months ago

A car traveling in a straight line has a velocity of 5.0m/s-1 at some instant. After 4.0s, it's velocity is 8.0m/s-1. What is it's average acceleration in this time interval?

Answers

Answered by rajsingh24

Explanation:

LET ASSUME,

u=5.0m/s ^-1

t=4.0s.

v=8.0m/s ^-1.

AVERAGE ACCELERATION =?

$a = \frac{(v - u)}{t} \\ a = \frac{(8.0 - 5.0)}{4.0} \\ a = \frac{3.0}{4.0} \\ a = 0.75\: ms {}^{2} \\ \\ hence.\\</p><p>the \: average \: acceleration \:in \:time \:interval \\= 0.75 \: ms {}^{2}$

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