A car traveling initially at 5.57 m/s accelerates at the rate of 0.923 m/s 2 for 2.68 s. What is its velocity at the end of the acceleration?
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Answered by
1
Answer:
FINAL VELOCITY = 20 m/sec
Explanation:
Initial Velocity (u) = 10 m/sec
Acceleration (a) = 5 m/sec2
Distance (s) = 30 m
Final velocity (v) = ??
Using Newton's Third law of Motion,
v2=u2+2as
v2=10 2+2×5×30
v2 = 100+300
v2 = 400
v = √400
v = 20m /sec
Answered by
1
Answer:
acceleration =( final velocity - initial velocity )/ time
Explanation:
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