Physics, asked by tameemtaj853, 11 months ago

A car traveling with a velocity of 80 km / hrslowed down to 44 km:/ hr in 15 sec the retardation

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Answered by sahuraj457
2
a = \frac{v - u}{t } \\ a = \frac{44 - 80}{ \frac{15}{3600} } \\ a = - \frac{3600 \times 36}{15} \\ a = - 8640kmph^(-2)
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