A car travelled (50 +- 0.3) m in (2 +- 0.1) sec. Find the relative error in its speed. (plz solve it) class 11
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Answered by
0
Answer:
relative error = ∆a/a
Step-by-step explanation:
0.1+0.3/50+2= 4/520=1/13
Answered by
30
Answer:
Answer in the picture ↗️
Or in the another way⬇️
V=time by distance=4.013.8=3.45
vΔv=dΔd+tΔt=13.80.2+4.00.3=0.089
ΔV=0.089×3.45=0.30
∴ Velocity =(3.45±0.3)m/s
percentage error =VΔV×100=0.089×100=8.9%
★【hope this helps u】★
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