A car travelled 70 km to the East of Patna and then
110 km to the West from there. How far from Patna
was the car finally ?
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Answer:-
Distance between Patna and final point of car
• Given:-
Car travelled 70 km to East of Patna.
Again travelled 110 km to the West from there.
• To Find:-
Total distance between the car and Patna.
• Solution:-
Let the starting point be A.
After travelling 70 km let that point be B
Final point after travelling 110 km be C
Diagram:-
Hence,
The distance formed is a right angle Traingle
Therefore,
Using Pythagoras theorem:-
(CA)² = (CB)² + (BA)²
→ (CA)² = (110)² + (70)²
→ (CA)² = 12100 + 4900
→ (CA)² = 17000
→ CA = √17000
→ CA = 130.38
Therefore, the distance between the final point and the starting point is 130.38 km.
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