Question

A car travelling along a straight road at 14metre per second is approaching traffic lights . The a driver apply the brokes and the comes to rest with constant deceleration .The distance from the point where brakes are applied to the point where car comes to rest in 14 metre find the deceleration of car​

Answer 1

Answer:

we know that

v^2 = u^2 +2as

here v= 0ms-1

u = 14ms-1

s=14m

here deceleration so a

then

2as = (0)^2 - (14)^2

2×a×14 = -14× 14

2a= -14

a=-7ms-2

-ve sing indicate speed is reducing