Question

a car travelling at 10 kilometre per hour up to 50 kilometre per hour at 20 seconds what is the distance and the acceleration travelled in the given time note convert the time into metre per second​

Answer 1

Explanation:

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Answer 2

$\sf{\underline{\large{\red{Question:-}}}}$

• initial velocity = u = 10km/hr
• final velocity = v = 50km/hr
• time taken = t = 20s
• acceleration = a
• distance = s

$\sf{\underline{\large{\red{Answer:-}}}}$

As the velocity is in km/hr and the time is in second, we will convert the velocity from km/hr to m/s by multiplying it with 5/18

u = 10km/h = (10 * 5/18) m/s = 2.78 m/s

v = 50km/h = (50 * 5/18) m/s = 13.89 m/s

t = 20s

$\underline{\mathtt{FINDING\: ACCELERATION:-}}$

$\underline{\boxed{\bf{\green{a\:=\:\frac{(v-u)}{t}}}}}$

$\implies$ a = $\frac{(13.89-2.78)}{20}$ m/s²

$\implies$ a = $\frac{11.11}{20}$ m/s²

$\implies$ a = 0.55 m/s²

$\underline{\mathtt{FINDING\:DISTANCE:-}}$

$\underline{\boxed{\bf{\green{s\:=\:ut +\: \frac{1}{2}at^{2}}}}}$

$\implies$ s = (2.78 * 20) + 1/2(0.55)(20 * 20) m

$\implies$ s = 55.6 + 110 m

$\implies$ s = 165.6 m

$\underline{\large{\mathtt{ANSWER:-}}}$

$\red{\sf{acceleration\:=\:0.55m/s^{2}}}$

$\red{\sf{distance\:=\:165.6m}}$