a car travelling at 108 kilometres per hour has its speed reduced to 36 km per hour while travelling a distance of 200 metres it acceleration and the time taken are
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Use equation v2=u2+2as
{here a comes out negative bcz speed decreases }
v=(108 x 5)/18= 30m/s Similarly u=10m/s s=200m
On solving You get a= -2m/s2
Using equation v=u+at you get t=10s
Explanation:
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