Question

a car travelling at 108 kilometres per hour has its speed reduced to 36 km per hour while travelling a distance of 200 metres it acceleration and the time taken are​

Answer 1

Answer:

Use equation v2=u2+2as

{here a comes out negative bcz speed decreases }

v=(108 x 5)/18= 30m/s   Similarly    u=10m/s    s=200m

On solving You get a= -2m/s2

Using equation v=u+at    you get  t=10s

Explanation: