A car travelling at 108 km/hour has its speed
reduced to 36 km/hour while travelling a
distance of 200 m. Its acceleration and the time
taken are
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u(initial velocity)= 108km/hr=30m/s
V(final velocity)= 36km/hr=10m/s
s(distance)= 200m
2as=v^2-u^2
2(a)200=900-100
2(a)=400
a=200m/s^2
a= v/t-u/t
200=30t-10t
200=20t
T=10s
Hope it helps
V(final velocity)= 36km/hr=10m/s
s(distance)= 200m
2as=v^2-u^2
2(a)200=900-100
2(a)=400
a=200m/s^2
a= v/t-u/t
200=30t-10t
200=20t
T=10s
Hope it helps
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