Question

a car travelling at 188 kmph has its speed reduced to 36 kmph while travelling a distance of 200 m calculate its retardation​

Answer 1

$\mathsf{\huge{Answer}}$

$\bold{Given\:that,}$

Intial velocity = 188km/h => 52.2 m/s

Final velocity = 36 km/h => 10 m/s

Distance = 200m

$\bold{We\:know\:that,}$

From 3rd equation of motion,

2as = $v^2 - u^2$

As it is retardation, so, a = - a

2(-a)(200) = $(10)^2 - (52.2)^2$

-400a = 100 - 2,724.84

-400a = - 2,624.84

$\cancel{-}400a = \cancel{-}2,624.84$

400a = 2,624.84

a = $\frac{2,624.84}{400}$

a = 6.5621

(Or) a = $6.6 m/s^2$