A car travelling at 20 ms-1 takes a u turn in 20s without changing its speed what is the averege acceleration of the car
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Explanation:
Initial speed of the car, u = 20 m/s
It takes u turn, so that, its final speed becomes, v = -20 m/s
Time, t = 20 s
To find,
The acceleration of the car.
Solution,
The rate of change of velocity is called acceleration of an object. It is given by :
\begin{gathered}a=\dfrac{v-u}{t}\\\\a=\dfrac{(-20)-20}{20}\\\\a=-1\ m/s^2\end{gathered}
a=
t
v−u
a=
20
(−20)−20
a=−1 m/s
2
So, the magnitude of of acceleration of the car is 1\ m/s^21 m/s
2
.
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Answer:
a=-2m/s^2
Explanation:
v=-20(as car takes u-turn , which is in opposite direction of motion)
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