Question

A car travelling at 20km/h speed up to 60km/h in 6 second what is its acceleration?

Answer 1

Answer:

24,000km/hr^2 or 1.246105919003m/s^2

Explanation:

given,

initial velocity, u = 20kmph

final velocity, v = 60kmph

time , t = 6 sec = 0.001666666666 hour

acceleration, a = v-u/t

a = 60-20/0.001666666666

a = 40/0.001666666666

a= 24,000km/hr^2 or 1.246105919003 m/s^2

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Answer 2

Answer:

$\large\dag \: \red{\underline{\tt Given:}}$

$\bullet\:\:\textsf{Time (t) = \textbf{6 seconds}}$

$\bullet\:\:\textsf{Initial velocity (u) = \textbf{20 km/hr}}$

$\bullet\:\:\textsf{Final velocity (v) = \textbf{60 km/hr}}$

$\qquad\tiny \dag\: \underline{\tt First \: of \: all \: we \: will \: convert \: all \: the \: given \: units \: of \: km/hr \: in \: m/sec : }$

$\dashrightarrow\:\:\sf Initial \: velocity \: (u)= 20 \: km/hr$

$\dashrightarrow\:\:\sf Initial \: velocity \: (u)= 20\times\dfrac{5}{18} \: m/sec$

$\dashrightarrow\:\:\sf Initial \: velocity \: (u)= \dfrac{50}{9} \: m/sec$

____________________

$\dashrightarrow\:\:\sf Final \: velocity \: (v)= 60 \: km/hr$

$\dashrightarrow\:\:\sf Final \: velocity \: (v)= 60 \times \dfrac{5}{18} \: m/sec$

$\dashrightarrow\:\:\sf Final \: velocity \: (v)= \dfrac{50}{3} \: m/sec$

_____________________

$\bigstar \: \boxed{\boxed{\sf Acceleration = \dfrac{Change \: in \: velocity}{Time \: taken}}} \: \bigstar$

$:\implies\sf Acceleration = \dfrac{Final \: velocity - Initial \: velocity}{Time \: taken}$

$:\implies\sf a = \dfrac{v - u}{t}$

$:\implies\sf Acceleration = \dfrac{\dfrac{50}{3} - \dfrac{50}{9}}{6}$

$:\implies\sf Acceleration = \dfrac{\dfrac{150 - 50}{9}}{6}$

$:\implies\sf Acceleration = \dfrac{\dfrac{100}{9}}{6}$

$:\implies\sf Acceleration = \dfrac{100}{54}$

$:\implies \underline{ \boxed{\sf Acceleration = 1.851 \: m/s^{2} }}$

$\therefore\:\underline{\textsf{The Acceleration produced is \textbf{1.851 m/s ^2 }}}.$