A car travelling at 20m/s along a road. A car runs out into the road 50 m ahead and a car driver step on the brakes pedal. What deacceleration be if the car is to stop just before it reaches the child
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Explanation:
u=20m/s
v=0 m/s
distance =20m
To find deacceleration .
we know third equation of motion .
v^2-u^2=2as
0^2-20^2 =2a20
-400=40a
a= -10 m/s^2.
hence deacceleration is -10 m/s^2.
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