a car travelling at 20m/s when the driver slams on the brakes and brings it to a straight line stop in 4.2s.what is the magnitude of its average acceleration
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Answered by
3
Given
u= 20
t = 4.2
V= 0
Using newtons equation
v= u + at
a= v-u/t= 0-20/ 4.2= 4.7 m/s^2
u= 20
t = 4.2
V= 0
Using newtons equation
v= u + at
a= v-u/t= 0-20/ 4.2= 4.7 m/s^2
Answered by
4
u=20m/s
t=4.2
v=0
a=(v-u)/t=0-20/4.2
a=-20/4.2
a=-4.76
so,the acceleration is negative
it means the magnitude of acceleration is opposite to the direction of velocity
t=4.2
v=0
a=(v-u)/t=0-20/4.2
a=-20/4.2
a=-4.76
so,the acceleration is negative
it means the magnitude of acceleration is opposite to the direction of velocity
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