Question

A car travelling at 36 km/h speeds up to 72 km/h in 5 seconds. What is its acceleration? (full process required)

Answer 1

$\large\bf\underline {To \: find:-}$

• we need to find Acceleration.

$\large\bf\underline{Given:-}$

• A car travelling at 36 km/h speeds up to 72 km/h in 5 seconds

$\huge\bf\underline{Solution:-}$

• Initial velocity (u) = 36km/hr
• Final velocity (v) = 72km/hr
• Time taken (t) = 5 seconds

Changing velocities in m/s

• 36km/hr = 10m/s
• 72k/hr = 20m/s

❥ By using 1st equation of motion:-

★ v = u + at

⠀⠀⠀⠀⠀➝ 20 = 10 + a × 5

⠀⠀⠀⠀⠀➝ 20 - 10 = 5a

⠀⠀⠀⠀⠀➝ 10 = 5a

⠀⠀⠀⠀⠀➝ a = 10/5

⠀⠀⠀⠀⠀➝ a = 2m/s²

hence,

• ≫Acceleration of car is 2m/s²

★━━━━━━━━━━━━━━━━━━━━

Acceleration :- The rate of change of velocity of an object with respect to time is called acceleration.

»★ Acceleration is a vector quantity.

»★ SI unit of acceleration is m/s²

━━━━━━━━━━━━━━━━━━━━★

Answer 2

Answer:

\large\bf\underline {To \: find:-}

Tofind:−

we need to find Acceleration.

\large\bf\underline{Given:-}

Given:−

A car travelling at 36 km/h speeds up to 72 km/h in 5 seconds

\huge\bf\underline{Solution:-}

Solution:−

Initial velocity (u) = 36km/hr

Final velocity (v) = 72km/hr

Time taken (t) = 5 seconds

Changing velocities in m/s

36km/hr = 10m/s

72k/hr = 20m/s

❥ By using 1st equation of motion:-

★ v = u + at

⠀⠀⠀⠀⠀➝ 20 = 10 + a × 5

⠀⠀⠀⠀⠀➝ 20 - 10 = 5a

⠀⠀⠀⠀⠀➝ 10 = 5a

⠀⠀⠀⠀⠀➝ a = 10/5

⠀⠀⠀⠀⠀➝ a = 2m/s²

hence,

≫Acceleration of car is 2m/s²

★━━━━━━━━━━━━━━━━━━━━

Acceleration :- The rate of change of velocity of an object with respect to time is called acceleration.

»★ Acceleration is a vector quantity.

»★ SI unit of acceleration is m/s²

━━━━━━━━━━━━━━━━━━━━★