Question

a car travelling at 36 km/he and acquired a velocity of 108 km/he in 5 sea then velocity of the car after 10 sec​

Answer 1

Answer:

We know that, 

Acceleration is defined as change in velocity in a particular period of time. It can be given as an equation. It is:

Acceleration = Change in Velocity / Time Taken

Change in Velocity = V - U

Here V represents Final Velocity, U represents Initial Velocity,

Therefore Change in velocity = 108 km/hr - 36 km/hr

=> Change in Velocity = 72 km/hr

We dont know the Time taken. But it can be found out by using this formula:

Time Taken = Total Distance / Change In velocity

=> Time Taken = 200 m / 72 km/hr

=> Time Taken = 200 m / 72 * 1000 m / 3600 sec

=> Time Taken = 200 / 72000 / 3600

=> Time Taken = 200 / 20 

=> Time Taken = 10 seconds

Therefore Acceleration = 20 m / sec / 10 sec

=> Acceleration = 2 m / s²

Therefore Acceleration = 2 m / s² and Time taken = 10 sec.

Hope it helped :-)

Answer 2

Hey there !

Solution :

We know that, 

Acceleration is defined as change in velocity in a particular period of time. It can be given as an equation. It is:

Acceleration = Change in Velocity / Time Taken

Change in Velocity = V - U

Here V represents Final Velocity, U represents Initial Velocity,

Therefore Change in velocity = 108 km/hr - 36 km/hr

=> Change in Velocity = 72 km/hr

We dont know the Time taken. But it can be found out by using this formula:

Time Taken = Total Distance / Change In velocity

=> Time Taken = 200 m / 72 km/hr

=> Time Taken = 200 m / 72 * 1000 m / 3600 sec

=> Time Taken = 200 / 72000 / 3600

=> Time Taken = 200 / 20 

=> Time Taken = 10 seconds

Therefore Acceleration = 20 m / sec / 10 sec

=> Acceleration = 2 m / s²

Therefore Acceleration = 2 m / s² and Time taken = 10 sec.

Hope it helped :-)