Question

a car travelling at 36 km/hr due north turns west in 5 s under constant accelerationand maintains the same speed. the acceleration of the car is

Answer 1

Initial velocity of car = 36 km/hr due north 
Final velocity of car = 36 km/hr due west

magnitude of change in velocity = $\sqrt{ 36^{2} + 36^{2} } = 36 \sqrt{2}$
(since velocity is a vector, so direction has to be taken into account)

Acceleration = $\frac{Change\ in\ velocity}{time}$ = $\frac{36 \sqrt{2} \times \frac{5}{18} }{5} = 2.828\ m/s^2$

(5/18 converts km/hr to m/s)

Answer 2

Answer:

2√2

Explanation:

south west .............................