a car travelling at 36 km /hr speed upto 72km/hr in 5 secs. what is the acceleration if the same car steps in 20 secs what is retardation
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Initial velocity u=36km/h=36X5/18=10m/s.
Final velocity v=72 km/h=20m/s.
Assuming uniform acceleration a=(v-u)/t=(20–10)/5=2m/s^2
For second part we take initial velocity=20m/s and final velocity =0m/s. t=20s is given.
Therefore ,retardation =(0–20)/20=-1m/s^2.
Final velocity v=72 km/h=20m/s.
Assuming uniform acceleration a=(v-u)/t=(20–10)/5=2m/s^2
For second part we take initial velocity=20m/s and final velocity =0m/s. t=20s is given.
Therefore ,retardation =(0–20)/20=-1m/s^2.
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