A car travelling at 36km per hour speeds up to 72 km per hour in five seconds.Find accleration ,if the same car stops in 20 seconds,calculate its negative acceleration (retardation}.(plz explain full answer.)
Answers
Answered by
6
1) v=72kmph or 72*5/18 =20 m/s
u = 36kmph or 36*5/18=10m/s
t =10 s
a=(v-u)/t
= 20-10/10=1m/s²
2) v=36kmph or 10m/s
u=0
t=20 s
a = V-U/T
= -10/20 =
-.05 m/s² or 0.5m/s² (retardation)
u = 36kmph or 36*5/18=10m/s
t =10 s
a=(v-u)/t
= 20-10/10=1m/s²
2) v=36kmph or 10m/s
u=0
t=20 s
a = V-U/T
= -10/20 =
-.05 m/s² or 0.5m/s² (retardation)
Similar questions