Question

A car travelling at 50m/s from rest covers a distance of 10km in 40min.calculate the the acceleration.

Answer 1

Aɴꜱᴡᴇʀ

☞ 12.5 m/s²

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Gɪᴠᴇɴ

➳ Final velocity (v) = 50m/s

➳ Initial velocity (u) = 0m/s

➳ Distance (s) = 10Km =10000m

➳ Time (t) = 40 seconds

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Tᴏ ꜰɪɴᴅ

➤ The acceleration of the body?

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Sᴛᴇᴘꜱ

❍ We have the initial,the final,the distance and the time , the formula that connects these is,

$\large {\underline{ \boxed{\sf{s = ut + \frac{1}{2}a {t}^{2} }}}}$

✭ Substituting the given values,

$\large \sf \dashrightarrow{}10000 = 0 \times 40 + \frac{1}{2} \times a \times {400}^{2} \\ \\ \large \tt \dashrightarrow10000= 800a \\ \\ \large \tt \dashrightarrow \frac{10000}{800} =a \\ \\\large{\tt{\pink{\dashrightarrow{12.5\:m/{s}^{2}}}}}$

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Answer 2

Answer:

answer is 1 / 288 m/s2 .

Explanation:

given

s=10Km :-10000m

U =0 as it is starts from rest

t= 40min :- 40×60 =2400s

a=?

s= ut + 1/2at^2

10000 =0×2400+1/2×a×2400×2400

:- a= 10000/2880000

=1/288m/s^2