A car travelling at 54 km/h is slowed down to 36 km/h in 10 sec. Find the retardation of the car (0.5m/s square)
Answers
Answered by
11
we have,
initial velocity=54 km/h
=15m/s
final velocity=36 km/h
=10m/s
time=10sec
since, acceleration= (final velocity-initialvelocity)/time
= (36-54)/10
= -1.8m/s^2
initial velocity=54 km/h
=15m/s
final velocity=36 km/h
=10m/s
time=10sec
since, acceleration= (final velocity-initialvelocity)/time
= (36-54)/10
= -1.8m/s^2
Siyella:
uhh i think that answer is wrong
shouldnt the velocity be in the same unit as time to actually make it an equation
your answer is wrong
see my answer
answer is -0.5m\s square
abhiraj 7 you first convert km\h into m\s
yeah thanks bro
Answered by
24
the answer is -0.5m\s square hope this will help you....
as (u)initial=54km\h
(v)final=36km\h
t=10sec
a=?
u=54km\h =1km\h=5\18m\s =54×5÷18=15m\s.
=54km\h=?
v=36km\h=same as. so,36×5÷18=10m\s.
a=v-u÷t so,10-15÷10=-0.5m\s square.
as (u)initial=54km\h
(v)final=36km\h
t=10sec
a=?
u=54km\h =1km\h=5\18m\s =54×5÷18=15m\s.
=54km\h=?
v=36km\h=same as. so,36×5÷18=10m\s.
a=v-u÷t so,10-15÷10=-0.5m\s square.
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