a car travelling at 54 kmph speeds up to 90 km/h in 2 seconds. find its acceleration. If the same car stop in 5 seconds calculate its negative acceleration
Answers
Answered by
19
Explanation:
The Brainliest Answer! In an inertial frame of reference, Speed=Distance/time. Therefore Distance traveled by the car=20*1m=20 meters!
Answered by
32
Answer:
Acceleration = 5 m/s²
Negative acceleration = -5 m/s²
Explanation:
Given:
- Initial velocity = u = 54 km/hr = 54×5/18 = 15 m/s
- Final velocity = v = 90 km/hr = 90×5/18 = 25 m/s
- Time taken = t = 2 seconds
To find:
- Acceleration of the car and ater speeding up its negative acceleration
Using the first equation of motion:
V=u+at
25=15+a×2
10=2a
a=10/2
a=5 m/s²
Now, second question:
Initial velocity = u = 25 m/s
Final velocity = v = 0 m/s
Time taken = t = 5 seconds
Using the first equation of motion:
0=25+a×5
-25=5a
a= -5 m/s²
The acceleration is equal to 5 m/s² and the negative acceleration is equal to - 5 m/s²
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