A car travelling at 54km/h. if brakes are applied so as to produce uniform retardation of 5mins square. calculate the time taken by it to stop
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v=0m/s
u=54km/h= 54×5/18= 15m/s
a= -5m/s^2
now by using first equation of motion
v=u+at
0= 15+(-5)t
-15= -5t
-15/-5=t
3s =t
u=54km/h= 54×5/18= 15m/s
a= -5m/s^2
now by using first equation of motion
v=u+at
0= 15+(-5)t
-15= -5t
-15/-5=t
3s =t
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