A car travelling at 60 km/h left Dehradun at 3 p.m. one her later another car travelling at 80 km per hour started from the same point and on the same road to overtake the first car how long was the second car travel to do so?
Answers
Answer:
= 3 hours and 240 km .
Step By Step Explaination
=> Let the time taken by second car overtake to the first car be x hours after it started.
=>Total time taken by first car = (x + 1) hours.
=> Total distance covered by first car in (x + 1) hours = 60(x + 1) km .
=>Distance covered by second car in x hours = 80x .
Thus, Distance coved by first car is equal to second car .
∴ 60(x + 1) = 80x .
=> 60x + 60 = 80x .
=>60 = 80 x - 60x .
=>60 = 20x .
∴ x = 3 .
Hence, the second car travelled in 3 hours to overtake the 1st car .
TO VERIFY: time taken by second car to overtake the first car = 80x = 80 × 3 = 240 km.
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Answer:
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