Question

A car travelling at 60 km/h
overtakes another car
travelling at 48km/h.
Assuming each car to be 5m
long, the time taken during
the overtake is​

Answer 1

Speed of the first car = 60 km/h

Speed of second car= 42 km/h

So, the relative speed of the first car with respect to the second car = 60-42 =18 km/h

To convert km/h to m/s we multiply the speed in km/h by 5/18.

So, relative speed = 18 × (5/18) = 5 m/s.

Now, as the first car overtakes the second car, it has to cover the second car's length as well it's own length. Understand it: the front part of the first car will first cover the length of the second car and then the rear part of the first car will cover the length of the second car.

Thus, in order to overtake, the first car covers a distance = 5+5 = 10m

So, time taken = (10/5) second = 2 second.

Now, in order to calculate road distance, time remains the same in every frame in this case. Thus, the total road distance covered by the first car = (Speed of 1st car)×(time that is taken in overtake) = (60 x (5/18))×2 m = 33.3 m

I hope it helps!