Question

A car travelling at 60 km/h overtakes another car travelling at 42 km/h. Assuming each car to be 5.0 m long, find the time taken during the overtake and the total road distance used for the overtake.Concept of Physics - 1 , HC VERMA , Chapter "Rest and Motion : Kinematics

Answer 1

Solution :

Car A speed =60km/hr=60x5/18=50/3 m/s

Car B speed =42km/hr=42x5/18=35/3 m/s

Relative speed of Car A w.r.t Car B is =50/3 - 35/3=15/3=5 m/s

Total distance to be covered in overtaking = Length of both cars =10m
Time =Distance/speed=10m/5m/s=2 sec

Total distance used for overatking will be equal to distance covered by car in overtaking + length of car
=(50/3)x2+5
=100/3 +5
=33.3+5
=38.3 m
∴time taken during the overtake and the total road distance used for the overtake is 38.3m

Answer 2

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