a car travelling at 60 km per hour left Dehradun and 3 p.m one hour later another car travelling at 80 km per hour started over the same Row 2 What is the first how long must the second car travel to overtake the first car
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D = v[t] . On overtaking ,both travel the same distance .
Let t = time the 2 nd car travels , then
80t =60[t+1]
20t =60
t=3 hrs
t+1=4 hrs
D=80[3]= 60[4]=240 km =overtaking distance.
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