Physics, asked by Aryan4545, 10 months ago

A car travelling at 60 km per hour overtake another car travelling at 42 kilometre per hour Assuming each car to be 5 metre long find the time taken during the overtake and the total road distance used for the overtake ??

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Answers

Answered by kancharlar71
0

Explanation:

ANSWER

The velocity of car which is overtaking v

1

= 60×5/18 = 50/3 m/s

The velocity of car to be overtaken v

2

= 42×5/18 = 35/3 m/s

The relative velocity between them v

12

=v

1

−v

2

= (50/3) - (35/3) = 5 m/s

The distance travelled by car 1 in overtaking car 2 = 10 m

∴Time taken in overtaking this distance = 10/5 = 2s

The distance travelled by car 1 in this duration

s = (50/3)×2 = 33.3 m

The total distance used for overtake = s + 5 = 33.3 + 5 = 38.5 m

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Answered by abhinavpandey8080
3

solutions

Velocity of car which is overtaking v1= 60×5/18=50/3 m/s

The velocity of car to be overtake V2=45×5/18=35/3 m/s

The relative velocity between them V12=v1--v2

(50/3)-(35/3)=5m/s

The distance travelled by car 1 in overtaking car. 2=10m

Time taking in overtaking this distance 10/5 =2s second

The distance travelled by car 1 in this duration

s=(50/3)×2=33.3m

The total distance used for overtake=s+5

=33.3+5= 38.5m..

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