A car travelling at 60 km per hour overtake another car travelling at 42 kilometre per hour Assuming each car to be 5 metre long find the time taken during the overtake and the total road distance used for the overtake ??
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Explanation:
ANSWER
The velocity of car which is overtaking v
1
= 60×5/18 = 50/3 m/s
The velocity of car to be overtaken v
2
= 42×5/18 = 35/3 m/s
The relative velocity between them v
12
=v
1
−v
2
= (50/3) - (35/3) = 5 m/s
The distance travelled by car 1 in overtaking car 2 = 10 m
∴Time taken in overtaking this distance = 10/5 = 2s
The distance travelled by car 1 in this duration
s = (50/3)×2 = 33.3 m
The total distance used for overtake = s + 5 = 33.3 + 5 = 38.5 m
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solutions
Velocity of car which is overtaking v1= 60×5/18=50/3 m/s
The velocity of car to be overtake V2=45×5/18=35/3 m/s
The relative velocity between them V12=v1--v2
(50/3)-(35/3)=5m/s
The distance travelled by car 1 in overtaking car. 2=10m
Time taking in overtaking this distance 10/5 =2s second
The distance travelled by car 1 in this duration
s=(50/3)×2=33.3m
The total distance used for overtake=s+5
=33.3+5= 38.5m..
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