a car travelling at 60 km per hour uniformly retards for 10 seconds and attain a velocity of 45 km per hour find retardation
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initial velocity ( u ) = 60 km/hr final velocity ( v ) = 45 km/hr time ( t )= 10 sec as a = {v - u} / t = (45 - 60)/ 10 = -15/10 so, retardation ( a ) = - 1.5 m/sec^2 #hope it helps
Strangercitizen1525:
tnx bro
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Hello user
Using the first equation of motion,we have
v=u+at
Here , t is 10 sec = 1/6 hours
So,
45 = 60 + 1/6 × a
a = -15 × 6 = -90 km/hr
So, retardation will be 90 km/hr
Using the first equation of motion,we have
v=u+at
Here , t is 10 sec = 1/6 hours
So,
45 = 60 + 1/6 × a
a = -15 × 6 = -90 km/hr
So, retardation will be 90 km/hr
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