Physics, asked by nareshmong3418, 1 year ago

A car travelling at 60km /h uniformly retards for 10s and reaches a velocity of 45 km/h. Find the retardation

Answers

Answered by vamsibat10
3
hey there here is your answer

initial velocity (u) = 60km/h = 50/3 m/s
final velocity (v) = 45km/h = 25/2 m/s
time = 10 s
retardation or negative acceleration
= v-u/t = 25/2 - 50/3 ÷10 =75-100 /60 = -25/60 = -5/12 = 0.416 m/s^2

hope it helps
Answered by Sammy2712
1
Acceleration=(Final velocity-Initial velocity)/Time

Multiply km/h with 5/18 to get m/s

60 km/h= 60*5/18=100/6 m/s

45 km/h= 45*5/18=75/6 m/s

a= [(100/6)-(75/6)]/10

a=(25/6)/10

a=5/12 m/(s^2)

Sammy2712: Plz mark it as the brainliest answer to your question
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