A car travelling at 60km /h uniformly retards for 10s and reaches a velocity of 45 km/h. Find the retardation
Answers
Answered by
3
hey there here is your answer
initial velocity (u) = 60km/h = 50/3 m/s
final velocity (v) = 45km/h = 25/2 m/s
time = 10 s
retardation or negative acceleration
= v-u/t = 25/2 - 50/3 ÷10 =75-100 /60 = -25/60 = -5/12 = 0.416 m/s^2
hope it helps
initial velocity (u) = 60km/h = 50/3 m/s
final velocity (v) = 45km/h = 25/2 m/s
time = 10 s
retardation or negative acceleration
= v-u/t = 25/2 - 50/3 ÷10 =75-100 /60 = -25/60 = -5/12 = 0.416 m/s^2
hope it helps
Answered by
1
Acceleration=(Final velocity-Initial velocity)/Time
Multiply km/h with 5/18 to get m/s
60 km/h= 60*5/18=100/6 m/s
45 km/h= 45*5/18=75/6 m/s
a= [(100/6)-(75/6)]/10
a=(25/6)/10
a=5/12 m/(s^2)
Multiply km/h with 5/18 to get m/s
60 km/h= 60*5/18=100/6 m/s
45 km/h= 45*5/18=75/6 m/s
a= [(100/6)-(75/6)]/10
a=(25/6)/10
a=5/12 m/(s^2)
Sammy2712:
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