A car travelling at 60km/hr overtakes another car traveling at 42km/hr. assuming each car to be 5m long, find the time taken during the overtake
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Hey.
Here is the answer.
Length of each car = 5 m
speed of 1st car = 60km/h =60×5/18=50/3 m/s
speed of 2nd car=42km/h =42×5/18=35/3 m/s
as both are traveling in the same direction, relative speed= 50/3 -35/3 m/s =15/3 m/s=5m/s
As time =distance travelled / speed
so, time required to overtake = sum of length of both cars / relative speed = 5+5 m / 5m/s
so, time taken =10/5 sec = 2 sec
Thanks.
Here is the answer.
Length of each car = 5 m
speed of 1st car = 60km/h =60×5/18=50/3 m/s
speed of 2nd car=42km/h =42×5/18=35/3 m/s
as both are traveling in the same direction, relative speed= 50/3 -35/3 m/s =15/3 m/s=5m/s
As time =distance travelled / speed
so, time required to overtake = sum of length of both cars / relative speed = 5+5 m / 5m/s
so, time taken =10/5 sec = 2 sec
Thanks.
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