Question

a car travelling at 60km ph overtakes another car travelling at 42kmph. Assuming each car to be 5 m long find the total road distance used for the overtake​

Answer 1

$\huge\mathfrak\green{Answer:-}$

Speed of car A =60km/hr

=60x5/18

=50/3 m/s

Speed of car B =42km/hr

=42x5/18

=35/3 m/s

Relative speed of Car A w.r.t Car B is =50/3 - 35/3

=15/3

=5 m/s

Total distance to be covered in overtaking = Length of both cars

=10m

We know Time =Distance/speed

=10m/5m/s=2 sec

Total distance used for overatking will be equal to distance covered by car in overtaking + length of car

=(50/3)x2+5

=100/3 +5

=33.3+5

=38.3 m

∴Time taken during the overtake and the total road distance used for the overtake is 38.3m

=60x5/18

=50/3 m/s

Hence the the total road distance used for the overtake is 50/3 m/s.

Answer 2

hope this helps u

mark BRAINLIEST