A car travelling at 80 m/s is braked so as to produce a retardation of 4 m/s2. After what time wil
its speed be 40 m/s and what will be the distance travelled during this time? (10 s; 600 m)
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Explanation:
u = 80m/s
v = 40m/s
a = -4 m/s²
From v = u + at,
40m/s = 80m/s - 4t
- 40 = - 4t
t = 10s
From S = ut + 1/2at²,
S = 80*10 - 2*100
S = 800 - 200
S = 600m
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