A car travelling at 80m/s is braked so as to produce a retardation of 4m/s^2. After what time will its speed be 40m/s and what will be the distance travelled during this time? (Please send me the solution with an attachment)
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Answered by
3
V = U + 2ad
(40)² = (80)² +2(-4)d
1600 = 6400 - 8d
1600 - 6400 = -8d
-4800 = -8d
-4800/-8 = d
600m = d
(40)² = (80)² +2(-4)d
1600 = 6400 - 8d
1600 - 6400 = -8d
-4800 = -8d
-4800/-8 = d
600m = d
Answered by
5
yaar physics newton likha hai ye question to banta hai???
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