a car travelling at 9 metre per second accelerated attains a speed of 87 metre per second in 5 seconds calculate the acceleration and the acceleration and the distance covered in second
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Explanation:
u = 9 m/s
v = 87 m/s
t = 5 sec
a = v-u
t
= 87-9
5
= 78 ÷ 5
= 15.6 m/s²
s = ut +½at²
= 9×5 + ½ × 15.6 × 5²
= 45 + 195
= 240 m
shubham5686673:
thanks yar
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