Question

A car travelling at a speed 54 km/h is brought to rest in90 s .Find the distance travelled by the car before coming to rest​

Answer 1

Explanation:

V = x / t

( 54 × 5 ) / 18 = x / 90

x = 54 × 5 × 90 / 18

x = 1350 m

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Answer 2

The initial velocity(u) of the car is = 54km/hr = 15m/s

The final velocity(v) of the car is = 0 m/s

The time taken(t) by the car to come to rest = 90 seconds

let distance = s

v² = u² + 2as

0 = 15² - 2*1/6*s

s = 225*3

s = 675 m