Question

A car travelling at a speed 72 km/hr is brought to rest in 40s. Find the distance travelled by the car

before coming to rest.

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Answer 1

Answer:

Here is your answer mate

Explanation:

Travelling car speed = 72 km / hr

So,

72 + 72

= 144 km

Bought to be rest = 40s

So,

40 x 144

= 5,760 km / hr

Answer 2

Answer:

The distance travelled by the car before coming to rest is 800 m.

Explanation:

Given, a car travelling at a speed 72 km/hr.

So,speed of the car is 72 km/hr$= 72 \times \frac{5}{18} = 4 \times 5 = 20$m/s.

And it is also given that after travelling the car is brought to rest in 40s.

So,here time is 40s.

We know,

$distance = time \times speed$

By one example we can understand this concept easily.

Let one bus has speed 20 m/s and the bus takes 5 s for covering a certain distance.Now question is what is the distance?

We know,

$distance = time \times speed$

$distance = 20 \times 5 = 100$m.

In the given question we know speed is 20 m/s and time is 40 s.

So,required distance is $(20 \times 40) = 800$m.

Therefore,the distance travelled by the car before coming to rest is 800 m.