A car travelling at a speed of 10m/s stops in 4 sec. after the application of brakes.If we assume the retardation to be constant, then a)Draw a speed - time graph for the above information. b) Find the retardation. c) Find the distance travelled during this time.
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Answered by
45
Initial speed = u = 10 m/s
time duration to stop = t= 4 s
Final speed = v = 0
Acceleration , magnitude = (v-u)/t
a = -10/4 = - 2.5 m/s^2
Distance covered before halting
s = u t + 1/2 a t^2
s = 10 * 4 - 1/2 * 2.5 * 4^2 m
s = 20 m
time duration to stop = t= 4 s
Final speed = v = 0
Acceleration , magnitude = (v-u)/t
a = -10/4 = - 2.5 m/s^2
Distance covered before halting
s = u t + 1/2 a t^2
s = 10 * 4 - 1/2 * 2.5 * 4^2 m
s = 20 m
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The graph is a straight line between two points: (1) speed = 10 m/s, time = 0s and (2) speed = 0 , time = 4 s. Join these two points. That is all. Easy.
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Answered by
29
Answer:
a) It is a straight line graph.
b) -2.5 m/s^2
c) 20 m
Explanation:
Applying the basic equations of kinematics in one dimension for uniform acceleration:
u = 10 m/s^2 . v = 0. t = 4 s.
b) a = (v - u)/ t = (0 - 10)/4 = -2.5 m/s^2
c) s = u t + 1/2 a t^2 = 10 *4 - 1/2 * 2.5 * 4^2 = 20 m
a) see graph enclosed.
Attachments:
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