Question

a car travelling at a speed of 30m/s is stopped by applying breaks which produces an acceleration of -2m/second square how much distance will be covered by it before it stops​

Answer 1

Answer:

a car moving with a velocity of 30 m/s is stopped by the application of breaks which impart a retardation ( negative acceleration) of 6 m/s² to the car.(1)how long does it take to come to rest(2)how far does the car travel during ...

Step-by-step explanation:

Answer 2

Correct Question:

A car travelling at a speed of 30m/s is stopped by applying breaks which produces an uniform acceleration of -2m/s². How much distance will be covered by it before it stops​?

Required Answer:

The car covers a distance of 225m.

Given:

• Initial Velocity(u) = 30m/s
• Final velocity = 0 (Since the car produces uniform acceleration).
• Acceleration = -2m/s²

To find:

We need to find the distance covered by the car before it stops.

Formula used:

We are going to use the below formula:

$\implies v^2-u^2=2as$

Solution:

$\implies v^2-u^2=2as$

$\implies 900 = -4 \times s$

$\implies s = \dfrac{900}{-4}$

$\implies s = 225m$

Therefore, the distance covered by the car is 225m.