a car travelling at a speed of 36km/hr is brought to rest by travelling a distance of 100m. if the mass of the car is 400 kg. find the retarding force and time taken by the car to stop
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HEY MATE HERE IS YOUR ANSWER
Mass of the car = 400kg
Initial velocity (u) = 36km/hr = 10m/s
Final velocity (v) = 0
Distance (S) = 100m
Applying v^2-u^2=2as
0^2 - 10^2 = 2×a×100
100 = 200a
a = -0.5
Retardation = -(a) = -(-0.5)
Retardation = 0.5m/s^2
Retarding force = Mass × retardation
= 400 × 2 = 800N
Applying s=ut+1/2at^2
100 = 10×t+1/2×0.5×t^2
t = 100 = 10.25
t = 9sec
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