Physics, asked by Vijisasikumar, 11 months ago

A car travelling at a speed of 54 k/h is brought to rest in 90seconds. Find the distance travelled by the car before coming to rest

Answers

Answered by slanzer
0

Answer:

d=speed/time

54/90

Explanation:

=0.6

Answered by streetburner
1

Answer:

675 m

Explanation:

v = 54 k/h = 54 * (5/18) = 15 m/s

v = u + at

0 = 15 - a (90)

a = 1/6

v^2 = u^2 + 2as

0 = 15*15 -2*(1/6)s

s = 225*3 = 675 m

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