Question

A car travelling at a uniform speed of 20 m/s approaches a signal. The driver applies the

brake and the car retards uniformly at the rate of 2 m/s2. How much time will be taken

by the car to come to rest?​

Answer 1

Explanation:

Write down all the information you have

vi = 20m/s

a = -2m/s/s

t = 5s

vf = ?

You can solve using:

vf = vi + at

vf = 20m/s + (-2m/s/s)(5s)

vf = 20m/s + (-10m/s)

vf = 10m/s

If a car moving at 20m/s is then slowed down by 2m/s/s for 5s, it’s final speed will be 10m/s

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Answer 2

Answer:

10 seconds

Explanation:

Given:

Initial velocity = u = 20 m/s

Acceleration = a = -2m/s²

Final velocity = v = 0 m/s (As the car finally comes to rest)

To find:

Time taken for the car to come to rest

Using the first equation of motion, which says:

V=u+at

Where:

v=final velocity

u=initial velocity

t=time

a=acceleration

Substituting the above values, we get:

0=20-2t

-20=-2t

t = $\frac{-20}{-2}$

t = 10 seconds

The car will take 10 seconds to come to rest