A car travelling at a velocity of 10 m/s due north speeds up uniformly to a velocity of 25m/s in 3 seconds, calculate acceleration during this time ?
rahulcool1029:
answers are ri8 and the process too
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Answered by
21
a= v-u/t
= 25-10/3
15/3
5 m/s²
= 25-10/3
15/3
5 m/s²
Answered by
15
v = u +at
a = (v-u)/t
a = (25 - 10)/3
a = 15/3
a = 5 m/s^2
a = (v-u)/t
a = (25 - 10)/3
a = 15/3
a = 5 m/s^2
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