Question

a car travelling at speed 54 km/h applies break and comes to rest after 5 seconds . find the acceleration and distance travelled.​

Answer 1

answer : a = -3m/s^2 s = 37.5 m

explation:

u(initial velocity) = 54km/h = 15 m/s

v(final velocity) = 0 km/h = 0 m/s

t(time) = 5s

a(acceleration) = v - u/t

a = 0 - 15/5

a = -15/5

a = -3 m/s^2

s(distance) = 2as = v^2 - u^2

2(-3)s = (0)^2 - (15)^2

-6s = -225

s = -225/6

s = 37.5 m