Physics, asked by acceptroshan3171, 9 months ago

A car travelling in a strainght line has a velocity of 5.0ms at some instant. After 4.0s,its velocity is 8.0ms. What is its average acceleration in thin time insterval?

Answers

Answered by lBrainlyHackerl
88

\huge\underline\blue{\rm Solution:}

\large\underline\purple{\rm Given: }

★Initial Velocity (u) = 5m/s

★Final Velocity (v) = 8m/s

★Time (t) = 4 sec

\large\underline\purple{\rm To\:Find: }

★Average Acceleration \rm{a_{avg}=?}

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We know ,

\large{\boxed{\rm a_{avg}={\frac{v-u}{t}}}}

\large\implies{\rm {\frac{8-5}{4}}}

\large\implies{\rm {\frac{3}{4}}}

\large\implies{\rm a_{avg}=0.75m/s^2}

\red{\boxed{\sf Averge\: Acceleration (a_{avg})=0.75m/s^2}}

Answered by deepvrm
2

Explanation:

initial velocity 8m/s

final velocity 5m/s

time interval 4 s

average acceleration (8-5)/4= .75ms^-3

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