A car travelling on a straight road at 15.0 meter per second accelerates uniformly to a speed of 21.0 meters per second in 12.0second. The total distance traveled by the car in this 12.0 second time interval is
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a =v-u /t
a=21-15/12=6/12=o.5mper s sqr
s =ut + 0.5 at sqr
s=12×15+0.5*0.5*12*12
=>18o +36=216 metres
a=21-15/12=6/12=o.5mper s sqr
s =ut + 0.5 at sqr
s=12×15+0.5*0.5*12*12
=>18o +36=216 metres
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